codeTest_and_Interview

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Interview Code Test

I am sharing some Code Test during my Interview, and also some practice Code example.
今天分享我一些Live Coding 面試問題，還有一些刷題的問題。

Amazon Live Code

Q1. read file into datastucture and search like logfile

If we have a log.txt, as below, you need to and search specfic string, like cat.

  • log.txt
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    1 cat
    2 lion
    3 apple

Answer 1: list

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with open("log.txt", "r") as textfile:
   lines = textfile.readlines()
for i in lines:
    sli = i.split(' ')
    #print(sli)
    if "cat" in sli:
        print(sli[0], sli[-1])

Answer2: using dictionary

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d={}
with open("log.txt", "r") as textfile:
   #lines = textfile.readlines()
#skip \n
   lines = textfile.read().splitlines()
   #print(lines)   
for i in lines:
    #sli = i.split(' ')    
    (key,val)=i.split(" ")
    d[int(key)]=val
   # print(key,"",val)
print(d)

HackCode

Q1. Alphabelt_filter

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class LetterFilter:

    def __init__(self, s):
        self.s = s      

# Enter your code here. 
# Complete the classes below.
# Reading the inputs and writing the outputs are already done for you.
#
# class LetterFilter:
#

  • Method 1: solution for HackCode

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    def eliminate_consonants(x):
            vowels= ['a','e','i','o','u']
            for char in x:
                if char not in vowels:
                    print(char, end = "")
    eliminate_consonants('mississippi')

  • Method 2: solution for HackCode

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    class LetterFilter:

        def __init__(self, s):
            self.s = s      

    # Enter your code here. 
    # Complete the classes below.
    # Reading the inputs and writing the outputs are already done for you.
    #
    # class LetterFilter:
    #
        #def __init__(self, s):
           #self.s = s
    	
        def filter_vowels(self):                
            # Enter your code here
            # Return a string       
            vowel = "aeiou"
            count = 0
            arr = []
            for y in self.s:
                if y in vowel:
                    arr.append(y)
                    count += 1
            result = self.convertListStr(arr)
            return result
                
        def filter_consonants(self):
            # Enter your code here
            # Return a string
            consonants = "bcdfghjklmnpqrstvwxyz"
            count = 0
    				arr = []
            #print(self.s)
            for y in self.s:
                if y in consonants:
                    arr.append(y)
                    count += 1
            result = self.convertListStr(arr)
            return result
        def convertListStr(self,text):        
            str= ""
            result = str.join(text)
            return result
    s = input("please enter string: ")
    f = LetterFilter(s)
    print(f.filter_vowels())
    print(f.filter_consonants())

Q2. Mutations

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STDIN           Function
-----           --------
abracadabra     s = 'abracadabra'
5 k             position = 5, character = 'k'

Solution

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def mutate_string(string, position, character):
    list1= []
    list1[:0]=string
    list1[position] = character  
    return "".join(list1)
if __name__ == '__main__':
    s = input()
    i, c = input().split()
    s_new = mutate_string(s, int(i), c)
    print(s_new)

Q3. fizz_buzz

Solution

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    def fizzBuzz(n): 
        # Write your code here
        for num in range(1, n+1):
            if num % 3 == 0 and num % 5 == 0:
                print("FizzBuzz")
            elif num % 3 is 0:
                print("Fizz")
            elif num % 5 is 0:
                print("Buzz")
            else:
                print(num)  
    if __name__ == '__main__':
        n = int(input().strip())
        fizzBuzz(n)
  • JS
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    var output = [];
    var count = 1;
    function fizzBuzz() {
      if (count % 3 == 0) {
        output.push("Bizz");
      } else {
        output.push(count);
      }
      count++;
      console.log(output);
    }

LeedCode